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1.
The average age of class of 24 students is 24 years. The average age increased by 1 when the teacher's age is also included. What is the teacher's age?
  • A.
    45
  • C.
    49
  • B.
    47
  • D.
    48
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Answer : [C]
Explanation :
 
  Average x Number = Total  
 
    24 years x 24 nos = 576 years ...(1)  
 
    25 years x 25 nos = 625 years ...(2)  
 
    Teachers age = (2) - (1)    
 
  = 625 - 576 = 49 years.  
 
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2.
When the present age of the father is added to the present age of the son, the sum is 40 years. What will be their total ages after 5 years?
  • A.
    40 years
  • C.
    35 years
  • B.
    45 years
  • D.
    50 years
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Answer : [D]
Explanation :
Let the present age of father be x
son's age = 40 - x
After 5 years,
father's age = x + 5
son's age = 40 - x + 5
Total age = x + 5 + 40 - x + 5 = 50 years
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3.
The average of class of 30 students is 21 years. When the teacher's age is included, the average increases by 1. What is teacher's age?
  • A.
    50
  • C.
    55
  • B.
    51
  • D.
    52
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Answer : [D]
Explanation :
 
    Average x Number = Total  
 
    30 nos x 21 years = 630 years ...(1)  
 
    31 nos x 22 years = 682 years ...(2)  
 
    Teacher's age = (2) - (1) = 682 - 630 = 52 years.  
 
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4.
The average age of class of 20 students is 20 years. If the teacher's age is included the average increases by 1. What is the age of the teacher?
  • A.
    40
  • C.
    31
  • B.
    41
  • D.
    42
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Answer : [B]
Explanation :
 
  Avg x Number = Total  
 
    20 nos x 20 years = 400 ...(1)  
 
    21 nos x 21 years = 441 ...(2)  
 
    Teacher's age = (2) - (1) = 441 - 400 = 41 years.  
 
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5.
The sum of the ages of a father and his two sons who are twins is 48. Ten years hence, his age will be twice the sum of the sonís ages. Find the present age of one son.
  • A.
    13 years
  • C.
    8 years
  • B.
    9 years
  • D.
    3 years
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Answer : [D]
Explanation :
Let the father's age be x and the age of each son be y.
Then, x + 2y = 48 -------------(1)
10 years hence,
  x + 10 = 2(y+10+y+10)
  x + 10 = 2(2y+20)
  x + 10 = 4y + 40
  x = 4y + 40 -10
  x = 4y + 30 --------(2)
Solving (1) and (2) we get
x + 2y = 48
Apply x value as 4y + 30 (as per (2))
  4y + 30 + 2y = 48
  6y + 30 = 48
  6y = 48 - 30
  6y = 18
  y = 18/6 = 3 (Present age of one son)
  x = 48 - (2 x 3)
  x = 48 - 6 = 42 (Present age of father)
Age of one son = 3 years and age of father = 42 years
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6.
The proportion between the current ages of A and B is 6 : 7. If B is 4 years older than A, What will be the proportion of the ages of A and B after Four years?
  • A.
    4 : 3
  • C.
    3 : 4
  • E.
    None of these
  • B.
    3 : 5
  • D.
    7 : 8
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Answer : [D]
Explanation :
Let A's age and B's age be 6x years and 7x years respectively
Then, B's age - A's age = 4
  7x - 6x = 4
  x = 4
So, A's age = 6x = 6 x 4 = 24
So, B's age = 7x = 7 x 4 = 28
After 4 years,
A's age = 24 + 4 = 28
B's age = 28 + 4 = 32
  Required ratio = 28 : 32 = 7 : 8  
 
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7.
The average age of a football team of 22 players is 21 years. The average increases by 1 when the coach's age also included. What is the age of the Coach?
  • A.
    40
  • C.
    44
  • E.
    None of these
  • B.
    41
  • D.
    43
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Answer : [C]
Explanation :
 
Average x Number = Total  
 
 21 years x 22 nos = 462 years ... (1)
 
 22 years x 23 nos = 506 years ... (2)
 
Coach's age = (2) - (1) = 506 - 462 = 44 Years.  
 
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8.
If Aadesh's age was one third of Aarush's age 5 years back and Aadesh is 17 years old now, How old is Aarush now?
  • A.
    40
  • C.
    36
  • B.
    41
  • D.
    48
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Answer : [B]
Explanation :
 
Aadesh's age today is 17 years,
 
Hence, 5 years back, he must be 12 years old
 
Thus, Aarush must be 36 years (3 x 12) old
 
After 5 years Aarush must be 41 years (36 + 5) old today.
 
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9.
The ages of Abhilash and Abhinav are in the ratio of 3 : 5. After 9 years, the ratio of their ages will become 3 : 4. The present age of Abhinav (in years) is
  • A.
    15
  • C.
    24
  • B.
    18
  • D.
    9
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Answer : [A]
Explanation :
 
Let Abhilash's age = 3x and Abhinav's age = 5x
 
  3x + 9 = 3    
5x + 9 4  
    4 (3x + 9) = 3 (5x + 9)  
    12x + 36 = 15x + 27  
    36 - 27 = 15x - 12x  
    9 = 3x  
    9/3 = x  
    x = 3  
   Abhinav's present age = 5x = 5x3 = 15 years.
 
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10.
The age of a mother is three times the sum of the ages of her two daughters. Five years hence, her age will be double of the sum of the ages of her daughters. The mother's present age is:
  • A.
    50 years
  • C.
    55 years
  • B.
    40 years
  • D.
    45 years
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Answer : [D]
Explanation :
 
Let the sum of present ages of the two daughters be x years.
 
Then, mother's present age = 3x years.
 
   (3x + 5) = 2 (x +10)        
 
 
3x + 5 = 2x + 20  
 
 
3x - 2x = 20 - 5  
 
 
x = 15  
 
Hence, mother's present age = 3x = 3 x 15 = 45 years.
 
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