Home
1.
How many of the following numbers are divisible by 3 but not by 9?
2133, 2343, 3474, 4131, 5286, 5340, 6336, 7347, 8115, 9276
  • A.
    5
  • C.
    7
  • B.
    6
  • D.
    None of these
  • Answer & Explanation
  • Report
Answer : [B]
Explanation :
 
Taking the sum of the digits, we have :
 
S1 = 9, S2 = 12, S3 = 18, S4 = 9, S5 = 21, S6 = 12, S7 = 18, S8 = 21, S9 = 15, S10 = 24.
 
Clearly, S2, S5, S6, S8, S9, S10 are all divisible by 3 but not by 9.
 
So, the number of required numbers = 6.
 
Report
Name Email  
2.
The difference between the squares of two consecutive odd integers is always divisible by:
  • A.
    3
  • C.
    7
  • B.
    6
  • D.
    8
  • Answer & Explanation
  • Report
Answer : [D]
Explanation :
 
Let the two consecutive odd integers be (2x + 1) and  (2x + 3)
 
Then, (2x + 3)2 - (2x + 1)2 = (2x + 3 + 2x + 1) (2x + 3 - 2x - 1) = (4 + 4) x 2
 
  = 8 (x + 1), which is always divisible by 8      
 
Report
Name Email  
3.
A positive integer, which when added to 1000, gives a sum which is greater than when it is multiplied by 1000. This positive integer is:
  • A.
    1
  • C.
    5
  • B.
    3
  • D.
    7
  • Answer & Explanation
  • Report
Answer : [A]
Explanation :
 
(1000 + N) > (1000N). Clearly, N = 1.
 
Report
Name Email  
4.
The smallest value of n, for which  2n + 1 is not a prime number, is:
  • A.
    3
  • C.
    5
  • B.
    4
  • D.
    None of these
  • Answer & Explanation
  • Report
Answer : [B]
Explanation :
 
(2 x 1 + 1) = 3, (2 x 2 + 1) = 5, (2 x 3 + 1) = 7. (2 x 4 + 1) = 9. which is not prime.
 
   n = 4.  
 
Report
Name Email  
5.
What largest number of five digits is divisible by 99?
  • A.
    99909
  • C.
    99990
  • B.
    99981
  • D.
    99999
  • Answer & Explanation
  • Report
Answer : [C]
Explanation :
 
Largest number of 5 digits = 99999. On dividing 99999 by 99, we get 9 as remainder.
 
    Required number = (99999 - 9) = 99990.  
 
Report
Name Email