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1.
Which is a valid unique-local address?
  • A.
    fec0:1111:2e3c:eab3::5/64
  • B.
    fe80:d2e1:e24:63::25/64
  • C.
    fd00:1edc:bae:eea4::2478/64
  • D.
    fc00:4fec:ecf2:343::e44/64
  • Answer & Explanation
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Answer : [C]
Explanation :
Although the unique-local address scope is defined as fc00::/7, RFC 4193 states that the 8th bit must equal a one for the local (L) bit. This requires the address to always start with fd which in binary is 1111 = f and 1101 = d or 1111 1101 = fd.
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2.
You are using the EUI-64 method of allocating the host portion of the IPv6 addresses. The MAC address of the host is 401e:32e4:ff03. What is the correct IP address that will be calculated for a network ID of fd00:3:3::?
  • A.
    fd00:3:3::fffe:421e:32e4:ff03/64
  • B.
    fd00:3:3::421e:32ff:fee4:ff03/64
  • C.
    fd00:3:3::401e:32ff:fee4:ff03/64
  • D.
    fd00:3:3::421e:32ff:ffe4:ff03/64
  • Answer & Explanation
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Answer : [B]
Explanation :
When converting a MAC address to an EUI-64 host address, the first step is to split the MAC address into 6-byte sections of 401e32 and e4ff03 and place fffe in between them: 401e:32ff:fee4:ff03. This gives you a 64-bit value comprised of a 48 bit MAC address and a 16 bit filler. You must then invert “flip” the 7th bit. Example: 40 = 0100 000 = flipped = 0100 0010 = 42.
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3.
You have been given an IPv6 address of 2030:3454:aabb::/64. What can you conclude?
  • A.
    The IP address is a unique-local address.
  • B.
    The IP has been given to you by the Regional Internet Registry.
  • C.
    The IP has been given to you by the Internet service provider.
  • D.
    The IP has been given to you by IANA.
  • Answer & Explanation
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Answer : [C]
Explanation :
The IPv6 address has been given to you by the ISP with your company’s unique identifier. The first 32 bits are allocated to the ISPs, and they in turn add a unique 16-bit address for your company. This makes 32 bits + 16 bits = 48 bits. You have 16 bits for subnetting after the first 48 bits to make a full 64-bit network ID.
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4.
Which type of address always uses the EUI-64 addressing mechanism?
  • A.
    Link-local addresses
  • B.
    Global unicast addresses
  • C.
    SLAAC addresses
  • D.
    Anycast addresses
  • Answer & Explanation
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Answer : [A]
Explanation :
Link-local addresses starting with fe80::/10 always configure the host portion of the address with an EUI-64 address. Note that Microsoft products default to a random host ID and can be configured to generate the host ID with EUI-64.
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5.
Which type of automatic address assignment will not allow for EUI-64 addressing?
  • A.
    Static addressing
  • B.
    SLAAC addressing
  • C.
    Stateful DHCPv6 addressing
  • D.
    Stateless DHCPv6 addressing
  • Answer & Explanation
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Answer : [C]
Explanation :
Stateful DHCPv6 addressing will not allow EUI-64 addressing. This is because the DHCPv6 server is responsible for allocating an IPv6 address from a predefined pool.
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