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56.
9572 – 4018 – 2164 =?
- A.3300
- C.3570
- B.3390
- D.7718
- Answer & Explanation
- Report
Answer : [B]
Explanation :
Explanation :
| 9572 - 4018 - 2164 = 9572 - (4018 + 2164) = (9572 - 6182) = 3390 |
57.
A boy multiplies 987 by a certain number and obtains 559981 as his answer. If in the answer, both 9's are wrong but the other digits are correct, then the correct answer will be:
- A.553681
- C.555681
- B.555181
- D.556581
- Answer & Explanation
- Report
Answer : [C]
Explanation :
Explanation :
| 987 = 3 x 7 x 47. | ||||
| So, required number must be divisible by each one of 3, 7, 47. | ||||
| None of the numbers in (a) and (b) are divisible by 3. While (d) is not divisible by 7. | ||||
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58.
The sum of first 45 natural numbers is :
- A.1035
- C.2070
- B.1280
- D.2140
- Answer & Explanation
- Report
Answer : [A]
Explanation :
Explanation :
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59.
There is one number which is formed by writing one digit 6 times (e.g. 111111, 444444 etc.). Such a number is always divisible by:
- A.7 only
- C.13 only
- B.11 only
- D.All of these
- Answer & Explanation
- Report
Answer : [D]
Explanation :
Explanation :
| Since 111111 is divisible by each one of 7, 11 and 13, so each one of given type of numbers is divisible by each one of 7, 11, 13, as we may write, 222222 = 2 x 111111, 333333 = 3 x 111111, etc. |
60.
A number when divided by 114 leaves the remainder 21. If the same number is divided by 19, then the remainder will be:
- A.1
- C.7
- B.2
- D.21
- Answer & Explanation
- Report
Answer : [B]
Explanation :
Explanation :
| Number = (114 x Q) + 21 = 19 x 6 x Q + 19 + 2 = 19 x (6Q + 1) +2. | |||
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