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16.
The least number by which 72 must be multiplied in order to produce a multiple of 112, is :
  • A.
    6
  • C.
    14
  • B.
    12
  • D.
    18
  • Answer & Explanation
  • Report
Answer : [C]
Explanation :
 
Required number is divisible by 72 as well as by 112, If it is divisible by their L.C.M, which is 1008.
 
Now, 1008 when divided by 72, Gives quotient = 14.
 
    Required number = 14.  
 
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17.
What should come in place of * mark in the following equation?
1*584    148 = 78    
  • A.
    1
  • C.
    6
  • E.
    None of these
  • B.
    4
  • D.
    8
  • Answer & Explanation
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Answer : [A]
Explanation :
 
Let
x
148
 = 78. Then, x = (148 x 78) = 11544    
 
    Required digit = 1  
 
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18.
(856 + 167)2 + (856 - 167)2
856 x 856 + 167 x 167
   is equal to :      
  • A.
    1
  • C.
    689
  • B.
    2
  • D.
    1023
  • Answer & Explanation
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Answer : [B]
Explanation :
 
Given Exp. =
(a + b)2 + (a - b)2
(a2 + b2)
=
2(a2 + b2)
(a2 + b2)
 = 2
 
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19.
A 3-digit number 4a3 is added to another 3-digit number 984 to give the four-digit number 13b7, which is divisible by 11. Then, (a + b) is :
  • A.
    10
  • C.
    12
  • B.
    11
  • D.
    15
  • Answer & Explanation
  • Report
Answer : [A]
Explanation :
 
 
4 a 3
9 8 4
1 3 b 7
     
    a + 8 = b     b - a = 8      
 
   Also, 13b7 is divisible by 11.
 
      (7 + 3) - (b + 1) = (9 - b)      (9 - b) = 0     b = 9.  
 
      b = 9 and a = 1     (a + b) = 10.  
 
 
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20.
A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is:
  • A.
    214
  • C.
    954
  • B.
    476
  • D.
    1908
  • Answer & Explanation
  • Report
Answer : [A]
Explanation :
 
 
4  x
5  y - 2
6  z - 3
   1 - 4
  z = 6 x 1 + 4 = 10

y = 5 x z + 3 = 5 x 10 + 3 = 53

x = 4 x y + 2 = 4 x 53 + 2 = 214 		 
 
Hence, required number = 214.
 
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