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- Problems on H.C.F and L.C.M
46.
The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is:
- A.1
- C.3
- B.2
- D.4
- Answer & Explanation
- Report
Answer : [B]
Explanation :
Explanation :
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| Now, co-primes with product 12 are (1, 12) and (3, 4). | ||||
| So, the required numbers are (13 x 1, 13 x 12) and (13 x 3, 13 x 4) | ||||
| Clearly, there are 2 such pairs. | ||||
47.
The product of two numbers is 1320 and their H.C.F. is 6. the L.C.M. of the numbers is:
- A.220
- C.1326
- B.1314
- D.7920
- Answer & Explanation
- Report
Answer : [A]
Explanation :
Explanation :
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48.
The least number of five digits which is exactly divisible by 12, 15 and 18, is:
- A.10010
- C.10020
- B.10015
- D.10080
- Answer & Explanation
- Report
Answer : [D]
Explanation :
Explanation :
| Least number of 5 digits is 10000. L.C.M. of 12, 15 and 18 is 180. | |||
| On dividing 10000 by 180, the remainder is 100. | |||
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49.
The H.C.F. and L.C.M. of two numbers are 11 and 385 respectively. If one number lies between 75 and 125, then that number is:
- A.77
- C.99
- B.88
- D.110
- Answer & Explanation
- Report
Answer : [A]
Explanation :
Explanation :
| Product of numbers = 11 x 385 = 4235. | ||||
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| Now, co-primes with product 35 are (1, 35) and (5, 7). | ||||
| So, the numbers are (11 x 1, 11 x 35) and (11 x 5, 11 x 7). | ||||
| Since one number lies between 75 and 125, the suitable pair is (55, 77) | ||||
| Hence, required number = 77 | ||||
50.
The greatest number which can divide 1356, 1868 and 2764 leaving the same remainder 12 in each case, is:
- A.64
- C.156
- B.124
- D.260
- Answer & Explanation
- Report
Answer : [A]
Explanation :
Explanation :
| Required number = H.C.F. of (1356 12), (1868 12) and (2764 12) | |||
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