- Home
- General Aptitude
- Problems on H.C.F and L.C.M
11.
The H.C.F. of two numbers is 12 and their difference is 12. The numbers are:
- A.66, 78
- C.94, 106
- B.70, 82
- D.84, 96
- Answer & Explanation
- Report
Answer : [D]
Explanation :
Explanation :
| Out of the given numbers, the two with H.C.F. 12 and difference 12 are 84 and 96 |
12.
The L.C.M. of 23 x 32 x 5 x 11, 24 x 34 x 52 x 7 and 25 x 33 x 53 x 72 x 11 is:
- A.23 x 32 x 5
- C.23 x 32 x 5 x 7 x 11
- B.25 x 34 x 53
- D.25 x 34 x 53 x 72 x 11
- Answer & Explanation
- Report
Answer : [D]
Explanation :
Explanation :
| L.C.M. = Product of highest powers of prime factors = 25 x 34 x 53 x 72 x 11 |
13.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
- A.4
- C.9
- B.7
- D.13
- Answer & Explanation
- Report
Answer : [A]
Explanation :
Explanation :
| Required number = H.C.F. of (91 – 43), (183 – 91) and (183 – 43) | ||||
|
||||
14.
The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is:
- A.1008
- C.1022
- B.1015
- D.1032
- Answer & Explanation
- Report
Answer : [B]
Explanation :
Explanation :
| Required number = (L.C.M. of 12, 16, 18, 21, 28) + 7 | |||
|
|||
|
|||
15.
The maximum number of students among them 1001 pens and 910 pencils can be distributed in such a way that each student gets the same number of pens and same number of pencils is:
- A.91
- C.1001
- B.910
- D.1911
- Answer & Explanation
- Report
Answer : [A]
Explanation :
Explanation :
| Required number of students = H.C.F. of 1001 and 910 = 91 |
|
|
||||||||||||||||||||||||||||
