- Home
- General Aptitude
- Problems on H.C.F and L.C.M
31.
Six bells commence tolling together and toll at intervals of 2, 4, 6, 8, 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together?
- A.4
- C.15
- B.10
- D.16
- Answer & Explanation
- Report
Answer : [D]
Explanation :
Explanation :
| L.C.M. of 2, 4, 6, 8, 10, 12 is 120. | ||||||||||||
| So, the bells will toll together after every 120 seconds, i.e, 2 minutes. | ||||||||||||
|
||||||||||||
32.
The H.C.F of 2923 and 3239 is :
- A.37
- C.73
- B.47
- D.79
- Answer & Explanation
- Report
Answer : [D]
Explanation :
Explanation :
|
||||||||||||||||||||||||||||
|
||||||||||||||||||||||||||||
|
||||||||||||||||||||||||||||
|
||||||||||||||||||||||||||||
|
||||||||||||||||||||||||||||
33.
The least number, which when divided by 48, 60, 72, 108 and 140 leaves 38, 50, 62, 98 and 130 as remainders respectively, is:
- A.11115
- C.15120
- B.15110
- D.15210
- Answer & Explanation
- Report
Answer : [B]
Explanation :
Explanation :
| Here (48 - 38) = 10, (60 - 50) = 10, (72 - 62) = 10, (108 - 98) = 10 & (140 - 130) = 10. | |||
|
|||
|
|||
|
|||
34.
The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:
- A.279
- C.308
- B.283
- D.318
- Answer & Explanation
- Report
Answer : [C]
Explanation :
Explanation :
|
||||||||
35.
The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is:
- A.3
- C.23
- B.13
- D.33
- Answer & Explanation
- Report
Answer : [C]
Explanation :
Explanation :
| L.C.M. of 5, 6, 4 and 3 = 60. | |||
| On dividing 2497 by 60, the remainder is 37. | |||
|
|||
|
|
||||||||||||||||||||||||||||
