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16.
If 2 tables and 3 chairs cost Rs. 3500 and 3 tables and 2 chairs cost Rs. 4000, then how much does a table cost?
  • A.
    Rs. 500
  • C.
    Rs. 1000
  • B.
    Rs. 750
  • D.
    Rs. 1500
  • Answer & Explanation
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Answer : [C]
Explanation :
 
Let the cost of a table and that of a chair be Rs. x and Rs. y respectively.
 
Then, 2x + 3y = 3500 …(i) and 3x + 2y = 4000 ….(ii)
 
Solving (i) and (ii), we get : x = 1000 and y = 500.
 
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17.
52.416 18.72 + 6.28 = ?    
  • A.
    2.09664
  • C.
    9.08
  • B.
    8.36
  • D.
    9.80
  • Answer & Explanation
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Answer : [C]
Explanation :
 
Given exp. =
5241.6
1872
  + 6.28 = 2.8 + 6.28 = 9.08  
 
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18.
(856 + 167)2 + (856 - 167)2
856 x 856 + 167 x 167
 = ?      
  • A.
    1
  • C.
    689
  • B.
    2
  • D.
    1023
  • Answer & Explanation
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Answer : [B]
Explanation :
 
Given exp. =
(a + b)2 + (a - b)2
a2 + b2
, where a = 856, b = 167    
 
  =
2(a2+ b2)
(a2 + b2)
 = 2.  
 
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19.
The price of 10 chairs is equal to that of 4 tables. The price of 15 chairs and 2 tables together is Rs. 4000. The total price of 12 chairs and 3 tables is:
  • A.
    Rs. 3500
  • C.
    Rs. 3840
  • B.
    Rs. 3750
  • D.
    Rs. 3900
  • Answer & Explanation
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Answer : [D]
Explanation :
 
Let the cost of a chair and that of a table be Rs. x and Rs. y respectively.
 
Then, 10x = 4y or y =
5
2
 x    
 
 
  15x + 2y = 4000    
 
 
  15x + 2 x
5
2
 x = 4000    
 
 
  20x = 4000    
 
 
  x = 200    
 
So, y =  
5
2
 x 200    = 500    
 
Hence, cost of 12 chairs and 3 tables = 12x + 3y = Rs. (2400 + 1500) = Rs. 3900.
 
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20.
The taxi charges in a city comprise of a fixed charge, together with the charge of the distance covered. For a journey of 16 km, the charges paid are Rs. 156 and for a journey of 24 km, the charges paid are Rs. 204. What will a person have to pay for travelling a distance of 30 km?
  • A.
    Rs. 226
  • C.
    Rs. 248
  • B.
    Rs. 240
  • D.
    Rs. 252
  • Answer & Explanation
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Answer : [B]
Explanation :
 
Let the fixed charge be Rs. x and variable charge be Rs. y per km.
 
Then, x + 16y = 156 …(i)   and    x + 24y = 204  …(ii)
 
Solving (i) and (ii), we get : x = 60, y = 6.
 
 
  Cost of travelling 30 km = Rs. (60 + 30 x 6) = Rs. 240.
 
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