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41.
If the simple interest on Rs. 3000 is less than the Simple Interest on Rs. 2000 at 5% by Rs. 50, find the time.
  • A.
    2
  • C.
    3
  • B.
    1
  • D.
    4
  • Answer & Explanation
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Answer : [B]
Explanation :
 
Here P1 = Rs. 3000  
  P2 = Rs. 2000  
 
Difference in interest = (Difference in P) x N x R  
100  
 
50 = 1000 x 5 x N ; N = 1 year  
100  
 
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42.
If Rs. 750 amounts to Rs. 1000 in 5 years, What will it become in 10 years at S.I.
  • A.
    1250
  • C.
    2050
  • B.
    1520
  • D.
    2000
  • Answer & Explanation
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Answer : [A]
Explanation :
 
P = 750; SI = 250; N = 5
 
Let the rate of interest be R
 
R = 100 x I = 100 x 250 = 20 %    
PN 750 x 5 3    
 

Amount in 10 years = 750 + 750 x

20 x 10    
3 100    
 
   = 750 + 500 = Rs. 1250  
 
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43.
The Sum of money that will produce Rs. 1770, interest in 7 1  years at 8% simple interest  
2  
per annum is
  • A.
    Rs. 2950
  • C.
    Rs. 2800
  • B.
    Rs. 3120
  • D.
    None of these
  • Answer & Explanation
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Answer : [A]
Explanation :
 
Here, I – Rs. 1770, R = 8% per annum, T = 15  years    
2    
 
 
 Principal (P) = 100 x I = 100 x 1770      
R x T
8 x 15
2
   
             
 
  = Rs. 2950  
 
 
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44.
If the simple interest on a certain sum of money for 2 years is one – fifth of the sum, then the rate of interest per annum is
  • A.
    9%
  • C.
    8%
  • B.
    10%
  • D.
    None of these
  • Answer & Explanation
  • Report
Answer : [B]
Explanation :
 
We have, T = 2 years.
 
Let the principal be Rs. x
 
Then, simple interest (I) = Rs. x  
5  
 
Rate of interest (R) =  
=
100 x x      
100 x I 5      
P x T x x 2      
 
  100  = 10% p.a.
5 x 2
 
 
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45.
A certain sum in invested for T years. It amounts to Rs. 400 at 10% per annum. But when invested at 4% per annum, it amounts to Rs. 200. Find the time (T).
  • A.
    41 years
  • C.
    50 years
  • B.
    39 years
  • D.
    None of these
  • Answer & Explanation
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Answer : [C]
Explanation :
 
We have, A1 = Rs. 400, A2 = Rs. 200, R1 = 10%, R2 = 4%
 
 
 Time (T) = A1 – A2  x 100    
A2R1 – A1R2    
 
  = 400 - 200 x 100 = 20000  = 50 Years.
200 x 10 - 400 x 4 400
 
 
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