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6.
In a game of 100 points A can give B 20 points and C 28 points. Number of points B can give C in a game of 100 points is
  • A.
    10
  • C.
    15
  • B.
    90
  • D.
    85
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Answer : [A]
Explanation :
 
A scores 100 while B scores 100 – 20 = 80 and C scores 100 – 28 = 72.
 
 
  While B scores 80, C scores 72  
 
 
  While B scores100, C scores
72
80
 x 100 = 90    
 
 
  B can give C 100 - 90 = 10 points.  
 
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7.
In a 200 metres rate A beats B by 35 m or 7 seconds. A’s time over the course is :
  • A.
    40 sec
  • C.
    33 sec
  • B.
    47 sec
  • D.
    None of these
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Answer : [C]
Explanation :
 
B runs 35 m in 7 sec.
 
 
  B covers 200 m in  
7
35
 x 200    = 40 sec.  
 
B's time over the course = 40 sec.
 
 
  A’s time over the course = (40 – 7) sec = 33 sec.  
 
 
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8.
A runs 1
3
4
 times as fast as B. If A gives B a start of 60 metres. How far must the winning    
post be in order that A and B reach it at the same time?
  • A.
    105 metres
  • C.
    140 metres
  • B.
    80 metres
  • D.
    45 metres
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Answer : [C]
Explanation :
 
Ratio of races of A and B = 7 : 4
 
i.e., 3 metres are gained by A in a race of 7 metres
 
 
  60 metres are gained by A in a race of  
7
3
 x 60    = 140 metres        
 
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9.
P can run a kilometre in 4 minutes 50 seconds and Q in 5 minutes. By what distance can P beat Q?
  • A.
    30 m
  • C.
    33
    1  m  
    3  
  • B.
    16
    2  m  
    3  
  • D.
    26
    2  m  
    3  
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Answer : [C]
Explanation :
 
Here P is the winner and Q is the loser.
 
 
 
Loser’s time
Winner’s distance
=
beat time + start time
beat distance + start distance
   
 
 
 
300
1000
=
10 + 0
beat distance + 0
     
 
 
  Beat distance =
100
3
 metres.    
 
 
  P beats Q by 33
1
3
 metres in 1 kilometre race.  
 
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10.
A, B and C are three participants in one km race. If A can give B a start of 40 metres and B can give C a start of 25 metres, how many metres A can give C a start?
  • A.
    64 m
  • C.
    60 m
  • B.
    32 m
  • D.
    44 m
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Answer : [A]
Explanation :
 
Here A is the winner (Ist)
 
Since B can give C a start therefore B becomes IInd and C becomes IIIrd in the race.
 
 
  (L - x12)x13 = L(x13 - x12)    
 
 
  (1000 - 40) x 25  = 1000 x (x13 - 40)    
 
 
  960 x 25  = 1000 x (x13 - 40)    
 
 
  (x13 - 40)  =
96 x 25
100
 = 24
 
 
  x13  = 64 metres    
 
Hence, A can give C a start of 64 metres.
 
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