6.
Mother's age today is thrice as her daughter's. After 10 years it would be just double. How much old is the daughter today?
- A.10
- C.9
- B.8
- D.11
- Answer & Explanation
- Report
Answer : [A]
Explanation :
Explanation :
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7.
The average age of class of 50 students is 24 years. If the average of 10 of them is 22 years, while average of another 10 is 26 years. What is the average of the remaining 30 students?
- A.22
- C.24
- B.32
- D.42
- Answer & Explanation
- Report
Answer : [C]
Explanation :
Explanation :
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| Observe that 10 students have an average of 22 years (2 years below 24). While another 10 students have an average of 26 years (2 years above 24). Thus, the effect by (-2) is nullified by the effect of (+2). As such, the average of remaining 30 students would remain same as 24 years. | ||||||||||
8.
The ages of Nirmal and Reena are in the ratio of 5:7. Sixteen years ago their ages were in the ratio of 3:5. The present age of Nirmal is
- A.35 years
- C.40 years
- B.45 years
- D.30 years
- Answer & Explanation
- Report
Answer : [C]
Explanation :
Explanation :
| Let the present age of Nirmal and Reena be x and y years. |
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| Using (1) and (2) we get | |||||||||
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| 25x - 21x = 160 | |||||||||
| 4x = 160 | |||||||||
| x = 40 | |||||||||
9.
Sangeetha is seven years older than Divya. Fifteen years ago, Divya’s age was three quarters of Sangeetha’s age. Find the age of Sangeetha now.
- A.41 years
- C.43 years
- B.36 years
- D.42 years
- Answer & Explanation
- Report
Answer : [D]
Explanation :
Explanation :
| Let Divya’s age = x years and Sangeetha’s age = x + 7 |
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| 4x – 60 = 3x – 24 |
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| x = 36 |
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| Sangeetha’s age = x + 7 = 36 + 7 = 43 years | |||||
10.
The ratio of the ages of mother to that of daughter is 7:3 today. After 5 years, this ratio would be 2:1. How many years old should the mother be at the time of birth of her daughter?
- A.18
- C.22
- B.21
- D.20
- Answer & Explanation
- Report
Answer : [D]
Explanation :
Explanation :
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