6.
In measuring the sides of a rectangle, one side is taken 10% in excess and the other 20% in deficit. Find the error per cent in area calculated from the measurement.
- A.12% deficit
- C.12% excess
- B.10% deficit
- D.None of these
- Answer & Explanation
- Report
Answer : [A]
Explanation :
Explanation :
Since side1 x side2 = area | |||||||||||||||
|
|||||||||||||||
|
|||||||||||||||
|
|||||||||||||||
|
|||||||||||||||
7.
Ram’s weight is 140% of Manu's weight. Tanu's weight is 90% of Mahesh's weight. Mahesh weighs twice as much as Manu. What percentage of Aseem's weight is Tan's weight?
- A.64.3%
- C.90%
- B.77.8%
- D.128.6%
- Answer & Explanation
- Report
Answer : [B]
Explanation :
Explanation :
If the weight of Manu is 50 kg them Ram's weight will be 70 kg. So, Mahesh's weight is 100 kg and Tanu's weight is 90 kg. Hence, percentage of Ram's weight to Tanu's weight | ||||||||
|
||||||||
8.
A number x is 125% of y. To comute y, the number x has to be multiplied by
- A.0.08
- C.0.8
- B.0.4
- D.None of these
- Answer & Explanation
- Report
Answer : [C]
Explanation :
Explanation :
We have, x = 125% of y | ||||||||||
|
||||||||||
|
||||||||||
|
||||||||||
|
||||||||||
9.
A shopkeeper has certain number of eggs of which 5% are found to be broken. He sells 93% of the remainder and still has 266 eggs left. How many eggs did he originally have?
- A.3,800
- C.6.5
- B.4,000
- D.None of these
- Answer & Explanation
- Report
Answer : [B]
Explanation :
Explanation :
Suppose the shopkeeper had x eggs, originally | |||||||||||
|
|||||||||||
|
|||||||||||
|
|||||||||||
|
|||||||||||
10.
A number is increased by 20% and then decreased by 20%, the final value of the number.
- A.does not change
- C.increases by 2%
- B.decreases by 2%
- D.decreases by 4%
- Answer & Explanation
- Report
Answer : [D]
Explanation :
Explanation :
Here, x = 20 and y = - 20 | ||||||||||
|
||||||||||
|
||||||||||
|
||||||||||
Since the sign is negative, there is decrease in value by 4% | ||||||||||