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16.
4.2 x 4.2 - 1.9 x 1.9
2.3 x 6.1
 = ?  
  • A.
    0.5
  • C.
    1.9
  • B.
    1
  • D.
    4.2
  • Answer & Explanation
  • Report
Answer : [B]
Explanation :
 
Given expression =
(a2 - b2)
(a + b)(a - b)
=
(a2 - b2)
(a2 - b2)
 = 1  
 
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17.
96.54 - 89.63
96.54 + 89.63
+
965.4 - 896.3
9.654 + 8.963
 = ?        
  • A.
    10-2
  • C.
     10
  • B.
    10-1
  • D.
    None of these
  • Answer & Explanation
  • Report
Answer : [A]
Explanation :
 
Given expressoion =
(96.54 - 89.63)
(96.54 + 89.63)
x
(9.654 + 8.963)
(965.4 - 896.3)
   
 
  =
(96.54 - 89.63)
(965.4 - 896.3)
x
(9.654 + 8.963)
(96.54 + 89.63)
   
 
  =
(96.54 - 89.63)
10 (96.54 - 89.63)
x
(96.54 + 89.63)
10 (96.54 + 89.63)
   
 
  =
1
10
x
1
10
=
1
100
-
1
102
 = 10-2      
 
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18.
  .00625 of
23
5
    when expressed as a vulgar fraction, equals:
  • A.
    		 23  
    80  
  • C.
    		 23  
    8000  
  • B.
    		 23    
    800  
  • D.
    		 125    
    23  
  • Answer & Explanation
  • Report
Answer : [B]
Explanation :
 
  .00625 of
23
5
  =  
625
100000
x
23
5
  =
23
800
   
 
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19.
617 + 6.017 + 0.617 + 6.0017 = ?
  • A.
    6.2963
  • C.
    629.6357
  • B.
    62.965
  • D.
    None of these
  • Answer & Explanation
  • Report
Answer : [C]
Explanation :
 
 
617.00
   6.017
   0.617
+ 6.0017
629.6357
 
   
 
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20.
The price of commodity X increases by 40 paise every year, while the price pf commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y?
  • A.
    2010
  • C.
    2012
  • B.
    2011
  • D.
    2013
  • Answer & Explanation
  • Report
Answer : [B]
Explanation :
 
Suppose commodity X will cost 40 paise more than Y after z years. Then,
 
(4.20 + 0.40z) - (6.20 + 0.15z) = 0.40
 
  0.25z = 0.40 + 2.10  
 
  z =
2.50
0.25
=
250
25
 = 10.      
 
   X will cost 40 paise more than Y 10 years after 2001 i.e., in 2011.  
 
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