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26.
In a 500 m race, the ratio of speeds of two contestants A and B is 3 : 4. A has a start of 140 m. Then A wins by
  • A.
    60 m
  • C.
    20 m
  • B.
    40 m
  • D.
    10 m
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Answer : [C]
Explanation :
 
To reach the wining post A will have to cover a distance of (500 140),
 
i.e. 360 m
 
While A covers 3 m, B covers 4 m
 
While A covers 360 m, B covers
4
3
 x 360 = 480 m  
 
So, A reaches the wining post while B remains 20 m behind.
 
 
  A wins by 20 m.  
 
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27.
A's speed is 1
1
2
 times of Bs. In a race A gives B a start of 300m. How long should    
the race course be so that both reach the winning post simultaneously?
  • A.
    700 m
  • C.
    800 m
  • B.
    900 m
  • D.
    850 m
  • Answer & Explanation
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Answer : [B]
Explanation :
 
A's speed : B's speed = 1
1
2
: 1 =
3
2
 : 1 = 3 : 2      
 
It means that in a race of 3 m, A gains (3 2) = 1 m over B
 
1 m is gained by A in a race of 3 m
 
 
  300 m is gained by A in a race of =
3
1
 x 300 = 900 m.  
 
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28.
A can run 330 metres in 41 seconds and B in 44 seconds. By how many seconds will B win if he has 30 metres start?
  • A.
    2 sec.
  • C.
    3 sec.
  • B.
    1 sec.
  • D.
    15 sec.
  • Answer & Explanation
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Answer : [B]
Explanation :
 
B runs 330 metres in 44 seconds.
 
 
  B runs (330 - 30) metres in
44
330
 x 300 secs.
 
i.e., 40 secs.
 
But A runs 330 metres in 41 seconds
 

So, B wins by (41 40) seconds, i.e., 1 second

 
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29.
In one km race A beats B by 5 seconds or 40 metres. How long does B take to run the kilometers?
  • A.
    125 sec
  • C.
    130 sec
  • B.
    120 sec
  • D.
    None of these
  • Answer & Explanation
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Answer : [A]
Explanation :
 
Time taken by A to complete the course =
5
40
 (1000 - 40) = 120 seconds      
 
 
  Time taken by B to run the km = (120 + 5) = 125 seconds  
 
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30.
In a 100 metres race A can give B 10 metres and C 28 metres. In the same race, B can give C
  • A.
    18 metres
  • C.
    27 metres
  • B.
    20 metres
  • D.
    9 metres
  • Answer & Explanation
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Answer : [B]
Explanation :
 
A : B : C = 100 : 90 : 72
 
 
  B : C =
90
72
=
  90 x
100
90
 
  72 x
100
90
 
=
100
80
 = (100 : 80)    
 
So, B can give C 20 metres.
 
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