46.
The population of a town is 50,000. It decreases by 20 per thousand per year. Find out the population after 2 years.
• A.
Rs. 46,000
• C.
Rs. 48,020
• E.
None of these
• B.
Rs. 46,200
• D.
Rs. 48,320
• Answer & Explanation
• Report
Answer : [C]
Explanation :

 Required population = Initial population 1 - r n 1000

 = 50,000 1 - 20 2 1000

 = 48,020

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47.
Rohit earns an interest of Rs 1656 for the third year and Rs 1440 for the second year on the same sum. Find the rate of interest if it is lent at compound interst.
• A.
18%
• C.
15%
• B.
12%
• D.
None of these
• Answer & Explanation
• Report
Answer : [C]
Explanation :

 Interest on Rs 1440 = Rs 216 for the third year

Rate % =   216 x 100  = 15
1440 x 1

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48.
If the difference between the simple interest and compound interests on some principal amount at 20% for 3 years is Rs. 48, then the principal amount is
• A.
Rs. 648
• C.
Rs. 375
• B.
Rs. 600
• D.
Rs. 350
• Answer & Explanation
• Report
Answer : [C]
Explanation :

 For three years

 Sum = x x (100)3 r2(300 + r)

 = 48 x (100)3 202 (300 + 20)

 = Rs. 375

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49.
What sum invested for 2 years at 12% compounded annually will grow to Rs. 4390.40?
• A.
Rs. 4000
• C.
Rs. 3800
• B.
Rs. 3500
• D.
Rs. 3875
• Answer & Explanation
• Report
Answer : [B]
Explanation :

 P 1 + R T = Amount 100

P  1 + 12 2  = 4390.40
100

P  112 2  = 4390.40
100

P 43904000  = 3500.
112 x 112

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50.
A sum of money is borrowed and paid back in two annual instalments of Rs. 882 each allowing 5% compound interest. The sum borrowed was:
• A.
Rs. 1620
• C.
Rs. 1680
• B.
Rs. 1640
• D.
Rs. 1700
• Answer & Explanation
• Report
Answer : [B]
Explanation :

Principal = (P.W. of Rs. 882 due 1 year hence) + (P.W. of Rs. 882 due 2 years hence)

882
 +
882
 1 + 5 100
 1 + 5 2 100
=
 882 x 20 + 882 x 400 21 441
= Rs. 1640

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